Botafogo RJ vs Atletico Mineiro
Brazil – Serie A
Date: Thursday, 20 August 2020
Kick-off at 1:30 UK/ 2:30 CET
Venue: Estadio Olimpico Nilton Santos (Rio de Janeiro).
Four consecutive draws in the schedule will not likely spice things up at the Botafogo camp in preparation to host Jorge Sampaoli and his troops.
The goalless draw on the road and consecutive away games in the league fixture will have effects on the home team. However, returning home will put them in their comfort zone looking for their maiden win.
Atletico MG is off to an impressive start in the league, winning all three fixtures so far this season. They are on a six-game winning streak in the campaign, following a 2-0 win at home against Ceara in their previous league clash in the schedule.
Four of their six games in the streak saw them keeping a clean sheet. It is likely to see the visitors create more chances in the encounter, but the host will not back up without a fight in ninety minutes.
Botafogo vs Atletico Mineiro Head-to-head (h2h)
- The visitor has recorded four of the last five overall wins.
- Their previous encounter gave a 2-0 home win for the Roosters.
- The Galo has kept a clean sheet in the previous five victories.
- The host has only three losses in the last ten clashes at home.
- Only one of their recent five fixtures has seen both teams score.
Botafogo vs Atletico Mineiro Prediction
Botafogo is on a winless streak in their schedule in the last four consecutive games across all major contests but has lost none in the process.
Goals have been scarce for the host in their fixtures, but the last time they hosted the Roosters, they won with a 2-1 scoreline. The tip for a BTTS will thus come in handy for the punters in ninety minutes.
In overall h2h meetings, Atletico MG has a better success rate than the host. So, a double chance favoring the visitor will probably be the best bet as the latter is on a winning streak in their schedule.
Botafogo vs Atletico Mineiro Betting tips
Draw no Bet Atletico @ 1.44 odd.
Both teams to score @ 1.83 odd.